Doc. # 1-0002673 | |||
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Date Updated | 07-27-2005 | Date Created | 07-27-2000 |
Document Type | Knowledge Base | Related OS | |
Related Product | PCL-839 |
How to calculate the time duration of the mentioned curve of PCL-839? | |||
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Solution:
Following is the answer of your inquiry.
R0=6750 steps
R1=0 PPS
R2=5000 PPS
R4=1023
R6:automatic ramping down point is enabled.
CLOCK=4.9152MHz
If set R7=600, then
FL=R1*CLOCK/(8192*R7)=R1=0
FH=R2*CLOCK/(8192*R7)=R2=5000
Psd={[(R2*R2)-(R1*R1)]*(R4)}/{16384*(R7)}=2602 steps
Tsd=2*Psd/(FL+FH)=1.0408 sec
Steps in constant speed FH (Pcs) = R0-Psd*2=6750-2602*2=1546 steps
Time period in constant speed FH (Tcs)=Pcs/FH=1546/5000=0.3092 sec
The acceleration rate is equal to deceleration rate.
So Total time(Tt)=Tcs+2*Tsd=0.3092+2*1.0408=2.3908 sec
Of course, Tt will depend on the value of R7.
Please also refer to user manual chapter 5 for further information.
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